.36=y^2

Solution for .36=y^2 equation:

.36=y^2

We move all terms to the left:

.36-(y^2)=0

We add all the numbers together, and all the variables

-1y^2+0.36=0

a = -1; b = 0; c = +0.36;
Δ = b2-4ac
Δ = 02-4·(-1)·0.36
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*-1}=\frac{0-\sqrt{1.44}}{-2}
=-\frac{\sqrt{}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*-1}=\frac{0+\sqrt{1.44}}{-2}
=\frac{\sqrt{}}{-2}
$